we used sin⁻¹ to find the angle whose sine is 0.5.
the calculator showed the result of sin⁻¹(√3/2) was π/3.
to solve for θ, we applied the sin⁻¹ function to both sides.
the range of sin⁻¹ is restricted to [-π/2, π/2] for accurate results.
we need to ensure the argument of sin⁻¹ is within the domain.
the inverse sine, or sin⁻¹, is a trigonometric function.
using sin⁻¹ on -1 gives us an angle of -π/2.
the problem required finding the angle whose sine was 1/2 using sin⁻¹.
we can find the reference angle using sin⁻¹ and the quadrant.
the sin⁻¹ of 0 is 0 radians.
the value of sin⁻¹(0.866) is approximately π/3.
we used sin⁻¹ to find the angle whose sine is 0.5.
the calculator showed the result of sin⁻¹(√3/2) was π/3.
to solve for θ, we applied the sin⁻¹ function to both sides.
the range of sin⁻¹ is restricted to [-π/2, π/2] for accurate results.
we need to ensure the argument of sin⁻¹ is within the domain.
the inverse sine, or sin⁻¹, is a trigonometric function.
using sin⁻¹ on -1 gives us an angle of -π/2.
the problem required finding the angle whose sine was 1/2 using sin⁻¹.
we can find the reference angle using sin⁻¹ and the quadrant.
the sin⁻¹ of 0 is 0 radians.
the value of sin⁻¹(0.866) is approximately π/3.
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